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Lithium battery boost module 5V Lithium ion battery charging module LED driving power module

Manufacturer
Manufacturer Product Number
M228
Description

Lithium battery boost module 5V Lithium ion battery charging module

Package Condition
Bulk
We are just Spot traders, Stockists, Sraders, PCBA&BOM service providers,Purchaser. All intellectual property rights of products on our website belong to the original factory! (In addition to ANSC's own customized products)

Product Parameters

1. Input voltage: DC5V-32V;

2. Output voltage: adjustable from DC0.8-30V;

3. Conversion efficiency: maximum 96%;

4. Output current: Maximum output current of 5A, adjustable;

5. Output power: maximum 75W;

Product Features

1. It can be used as a common voltage reduction module with overcurrent protection capability;

2. Can be used as a battery or battery charger;

3. Can be used as a high-power LED constant current drive module;

4. It has two modes: constant current and constant voltage, and an indicator light to indicate which mode it is currently in;

5. When used as a lithium battery charger, the float charging voltage and charging current can be set with indicator lights to indicate whether it is charging or fully charged;

6. It has a current limiting protection function, which will not burn out the module even if the output is short circuited.

Product Use

(1) After power on, adjust the voltage potentiometer to make the output voltage reach the ideal voltage;

(2) Measure the output short-circuit current with a multimeter in 10A current mode (simply connect the two probes to the output terminal), and adjust the current potentiometer to achieve the predetermined overcurrent protection value for the output current. (For example, if the current value displayed on the multimeter is 4A, then when you use the module, the high current can only reach 4A. When the current reaches 4A, the red constant current indicator light will turn on, otherwise the indicator light will turn off.)

Attention: When used in this state, due to the 0.05 ohm current sampling resistor at the output terminal, there will be a 00.3V voltage drop when connected to the load, which is a normal phenomenon! This voltage drop is not caused by your load, but by the sampling resistor.

2. Used as a battery charger

Modules without constant current function cannot be used to charge batteries. Due to the large voltage difference between the depleted battery and the charger, the charging current is too high, causing battery damage. Therefore, constant current charging should be used for the battery at the beginning, and when it reaches a certain level of charging, it will automatically switch back to constant voltage charging.

Usage method:

(1) Determine the float charging voltage and charging current of the rechargeable battery you need; If the parameters of the lithium battery are 3.7V/2200mAh, then the float charging voltage is 4.2V and the maximum charging current is 1A, which is 2200mAh;

(2) Under no-load conditions, measure the output voltage with a multimeter and adjust the voltage potentiometer to achieve the floating charge voltage; If charging a 3.7V lithium battery, adjust the output voltage to 4.2V;

(3) Measure the output short-circuit current with a multimeter in 10A current mode (simply connect the two probes to the output terminal), and adjust the current potentiometer to achieve the predetermined charging current value;

(4) The default factory charging current for switching from charging to lighting is 0.1 times the charging current; (The current of the battery gradually decreases during the charging process, gradually shifting from constant current charging to constant voltage charging. If the charging current is set to 1A, when the charging current is less than 0.1A, the red charging indicator light will turn off and the red fully charged indicator light will turn on, indicating that the battery is fully charged.);

(5) Connect the battery and charge it.

Attention: Steps (1), (2), (3), and (4) are: Connect the input terminal to the power supply, and the output terminal is unloaded without connecting the battery.

1. Used as a high-power LED constant current driver module

(1) Determine the operating current and voltage required to drive 1ED;

(2) Under no-load conditions, measure the output voltage with a multimeter and adjust the voltage potentiometer to reach the high operating voltage of the LED;

(3) Measure the output short-circuit current with a multimeter in 10A current mode, and adjust the current potentiometer to achieve the predetermined LED working current;

(4) Connect the LED and test the machine.

Attention: Steps (1), (2), and (3) are: Connect the input terminal to the power supply, and do not connect the output terminal to the LED light when there is no load

Product Funtions

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Payment&Transportation

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Official Certificate&Certificate

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Multiple product supply

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Lithium battery boost module 5V Lithium ion battery charging module LED driving power module

Lithium battery boost module 5V Lithium ion battery charging module

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